MEDEL!!! 2x - y = 5 x + 3y = 7 What is the value of the system determinant?
you can solve this using elimination or substitution; does the problem specify which one you should use?
multiply second equation with 2 and solve it
x terms will be cancelled
that would be elimination @rathanreddy
2x=6y=14 is what is would become
k sorry i ddn't see it
and actually @rathanreddy that is incorrect b/a it should be -2 to eliminate the other
he is looking for the determinant....this is not a square matrix....I do not know how to make your equations into a square matrix in order to find the determinant.
ya when we solve we can change the signs
|dw:1374806133207:dw| @Jamierox4ev3r
it has to be square, doesn't it....this is a 2x3 matrix....if it was a 2x2 or a 3x3 you could find the determinant...
You can use substitution or elimination
wait...are you solving for the system of equations or are you looking for the determinant ?
then use the way i told above you will get x and y
in this one the determinant
then you cant solve by elimination you should use determinant
I do not believe you can solve for the determinant if the matrix is not square...you have a 2x3 matrix...it is not square
@skullpatrol ....please take a look at this
@timo86m ...help
@johnweldon1993 ..help
determinant = 2(3) - (-1)(1) = 6+1=7
am i right?
I am not sure
@kropot72 ...please take a look at this
@satellite73 ....we need your assistance
@satellite73
Hmm from what I can remember about linear equations and determinants....there are both an 'x' and a 'y' determinant....are you sure the question doesn't specify for either one?
Or there is just a coefficient determinant...I'm not sure which you need...if you need the coefficient determinant...than @DontLikeMathButOhWell would be correct here...
By any chance zachary, is this multiple choice ?....lol
7 9 22
you might want to go with @DontLikeMathButOhWell ....go with 7
Yeah the 7 would look correct to me too lol
thanks john for coming and looking....good job Dontlikemath
Yay :D, I feel accomplished
Lol good job @DontLikeMathButOhWell And no problem @texaschic101 :)
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