Question

find the derivative of-
(x+s)(sqrt(3s^2+2sx-x^2))/4

Answer 1

\[((x+s)(\sqrt{3s ^{2}+2sx-x ^{2}}))\div2\]

Answer 2

Is it/4 or /2?

Answer 3

derivative with respect to what?
d/dx or d/ds

Answer 4

/4 sorry

Answer 5

and d/dx

Answer 6

everytime I attempt it, it gets real messy, real fast

Answer 7

\(u = x + s\)

\( v = (s^2 + 2sx - x^2)^{ \frac{1}{2} } \)

\(f(x) = uv\)

\(f'(x) = uv' + vu' \)

Answer 8

\(u' = 1\)

\(v' = \dfrac{1}{2}(s^2 + 2sx - x^2)^{-\frac{1}{2}} (2s - 2x) = (s^2 + 2sx - x^2)^{-\frac{1}{2}} (s - x) \)

Answer 9

there was a three in front of the s^2

Answer 10

ohhhh I got it from here

Answer 11

thanks a bunch

Answer 12

Wlcm.
Remember the 3 I left out, and remember the /4 which is just a constant.