You roll 2 die. What is the probability that the sum of the dice is greater than 8 and that 1 die shows a 6?
I'm a bit confused with this problem because the second clause (at least one die must show a 6) interferes with the first - ie In order to have more than 8 as a total, you must leave out '4' and '4' for the second part.
Can anyone help?

Question

You roll 2 die. What is the probability that the sum of the dice is greater than 8 and that 1 die shows a 6? 
I'm a bit confused with this problem because the second clause (at least one die must show a 6) interferes with the first - ie In order to have more than 8 as a total, you must leave out '4' and '4' for the second part. 
Can anyone help?

anonymous · Answer

lets count

anonymous · Answer

(6,3),(6,4),(6,5),(6,6),(3,6),(4,6),(5,6) am i missing any?

wach · Answer

I think that's correct, to fulfill the requirements?

wach · Answer

Ohhh. Psh, I'm silly. Thank you.

anonymous · Answer

ok then the number of favorable ones above, divided by the total which is 36

anonymous · Answer

yw

wach · Answer

If I had a more complicated problem with more die than I could count, is there some sort of formula/method I could use?

anonymous · Answer

i like counting

anonymous · Answer

with dice it is easiest
you can verify that whatever formula you use is correct with dice however

anonymous · Answer

but it is almost always more complicated to use a formula

wach · Answer

Alrighty, thanks ~