Question

question is attached...

Answer 1

where? lol

Answer 2

what is that ? :o
its just full of f >.<

Answer 3

:( what why?

Answer 4

? :/

Answer 5

:p what the crap. I have no clue why its like that...

Answer 6

Same here i see all Fs too.

Answer 7

Oh i can see it now.

Answer 8

get the probability of a 55 year old person or older
100 out of 300 = 1/3

Then find the probability of a 55 year old person or older having a shot
90 out of 100 = .9

And so .9 * 1/3 is .3
Your answer is...

Answer 9

.33

Answer 10

Yes :)

Answer 11

thank u!

Answer 12

ok what abt this now?

Answer 13

I'll try ma best.

Answer 14

then howd u see the last question??

Answer 15

ok

Answer 16

what

Answer 17

http://assets.openstudy.com/updates/attachments/51f1e7f5e4b0c8f6bc355046-music101-1374809384166-question2.rtf

Answer 18

...so u don't know it??

Answer 19

:( darn it

Answer 20

@mary.rojas

Answer 21

if u cant read it here's the problem:

Answer 22

true or false:
For any two events X and Y, P(Y|X)+P(X|Y)=0

Answer 23

anyone know?

Answer 24

DURING MY RESEARCH, I FOUND THIS: LOL HOPE IT HELPS
P(X|Y) = P(X n Y) / P(Y)
P(Y|X) = P(Y n X) / P(X)

Now, X n Y = Y n X, so P(X n Y) = P(Y n X). That means that P(X|Y) = P(Y|X) is equivalent to:

P(X n Y) / P(Y) = P(X n Y) / P(X)
P(X)P(X n Y) = P(Y)P(X n Y)
P(X)P(X n Y) - P(Y)P(X n Y) = 0
(P(X) - P(Y))P(X n Y) = 0
P(X) = P(Y) or P(X n Y) = 0

That is, the above is true if and only if X and Y are equally likely, or if X and Y are mutually exclusive. Oh, and since we were dividing by P(X) and P(Y), both must be possible, i.e. non-zero probability.

So, in general, this is false. Let's find an example. Say you have two coins, and you flip them both simultaneously. Let:

X = at least one head
Y = two heads

Notice that X and Y are not mutually exclusive, and that P(X) = 1/2, P(Y) = 1/4, so they have both non-zero probabilities and are not equally likely. This should indicate that P(X|Y) does not equal P(Y|X).

P(X|Y) = 1
P(Y|X) = 1/2

That's a counterexample, so the equation is false.

Answer 25

wow. ok thank u :)

Answer 26

HERE IS THE LINK : http://answers.yahoo.com/question/index?qid=20100802180944AAiWVD3 SCROLL DOWN

Answer 27

is ur answer just based on that??

Answer 28

yea tats what I was thinking..

Answer 29

that's

Answer 30

if I miss one im already at like an A- or even a B plus...

Answer 31

yes my answer is based on that because I have no clue how to help you lol. But I gave you the link so, you could see a similar if not the same kind of problem to help you get an answer. sorry :/
theres another reply as well. i know u hate that website but sometimes it can be right. hopefully someone else can help u more

Answer 32

ok.. so I guess ill say false then..

Answer 33

wait did u see the link because it is a different q
but similar kind

Answer 34

yea but I still don't know how to do it..

Answer 35

*q=question btw

Answer 36

i know that

Answer 37

oh ok lol

Answer 38

isn't there anyone else who knows this? :/

Answer 39

@mathstudent55 help?

Answer 40

@primeralph help? :)

Answer 41

Can't get to the file. Need screenshot.

Answer 42

this is the question:

Answer 43

True or False:
For any two events X and Y, P(Y|X)+P(X|Y)=0

Answer 44

Is that all?

Answer 45

@music101

Answer 46

yes

Answer 47

Appears false.

Answer 48

@Luis_Rivera

Answer 49

I'd say false.

Answer 50

ok thank uall

Answer 51

next q:

Answer 52

You roll two dice. let event A be "The first die shows a 1 or a 6" and event B "The second die shows an even number." What is P(A|B)?

Answer 53

is it 1/3?

Answer 54

@benhan0406 do u know?

Answer 55

i found this :
I think some people are confused about your notation.
I interpret this as "the probability of A such that B", but I'm not sure what you mean. If that is what it means, this is it.

(1/3)*(1/2)=(1/6)
A B

If that seems wrong, post again with more information

Answer 56

and this:
P(B) = 3/6 = 1/2
P(A and B) = 1/6
P(A|B) = P(A and B) / P(B)
= (1/6) / (1/2) = 1/3

Answer 57

ok... but the way they got 1/3 is (1/6)*(1/2) ??? (1/6)*(1/2)= 1/12...

Answer 58

@blurbendy

Answer 59

no its (1/6) / (1/2) = 1/3... dividing not multiplying. !!!

Answer 60

ohhhhhhhhh the first one is multiplying i seee

Answer 61

oh ok well I said 1/3 anyways

Answer 62

yea..

Answer 63

hmmmm idk....... do you multiply or divide?

Answer 64

wait here's new question instead and don't do research...

Which choice correctly expresses the probability of the following?
"What is the probability that I will ace this quiz? I mean, I did study awfully hard for it."

A. P(I ace the quiz) I P(I studied hard)
B. P(I ace the quiz and I studied hard)
C. I ace the quiz | I studied hard
D. I ace the quiz and I studied hard
E. P( I ace the quiz | I studied hard)