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Mathematics 23 Online
OpenStudy (anonymous):

Please check my work and correct me on the wrong ones

OpenStudy (anonymous):

OpenStudy (calculusfunctions):

@Chicken_Nuggets_ #1, 4, 5, 9, and 10 are incorrect.

OpenStudy (calculusfunctions):

Since @BarbaraKara already helped you with #1, let's start with #4, shall we? Let me know whenever you're ready.

OpenStudy (anonymous):

I am ready

OpenStudy (calculusfunctions):

#4). A bag has 5 red marbles, 6 blue marbles and 4 black marbles. What is the probability of picking a black marble, replacing it, and then picking a blue marble? First of all how many marbles do we have in total? How many of these are black?

OpenStudy (anonymous):

15 total and 4 black

OpenStudy (calculusfunctions):

Correct! thus what is the probability of selecting a black marble?

OpenStudy (anonymous):

4/15?

OpenStudy (calculusfunctions):

Yes! Now you're replacing it, which means you're putting it back so then you would still have a total of 15 marbles. Agree? Now how many are blue and hence what is the probability of selecting a blue marble?

OpenStudy (anonymous):

5 red so the probability would be 5/15

OpenStudy (calculusfunctions):

No sorry, I meant blue. I changed it. Read it again.

OpenStudy (anonymous):

6/16

OpenStudy (calculusfunctions):

6/16? An extra marble was added?? Don't you mean 6/15?

OpenStudy (anonymous):

No 6/15 sorry lol

OpenStudy (calculusfunctions):

Yes. So now what do you do to get the final answer?

OpenStudy (anonymous):

Umm, multiply?

OpenStudy (calculusfunctions):

Yes so then what do get as the final answer. Reduce all final fractions to lowest terms.

OpenStudy (calculusfunctions):

(4/15)(6/15) = ??

OpenStudy (anonymous):

8/75

OpenStudy (calculusfunctions):

Yes!

OpenStudy (anonymous):

Thanks!

OpenStudy (calculusfunctions):

Now #5). In how many different ways can Ally, Ben, Candy, Doug, Ed and Francis line up for lunch? How many people need to be arranged to form a queue?

OpenStudy (anonymous):

6

OpenStudy (calculusfunctions):

Correct! So how many ways can this be done, if the number of arrangements of n distinct members is given by n!

OpenStudy (calculusfunctions):

That's n factorial (n!)

OpenStudy (anonymous):

120?

OpenStudy (calculusfunctions):

NO...What is 6 factorial? It's 6 X 5 X 4 X 3 X 2 X 1. What does that equal?

OpenStudy (anonymous):

720!

OpenStudy (calculusfunctions):

Yes to 720. NOT 720 factorial. LOL

OpenStudy (anonymous):

Lol alright

OpenStudy (calculusfunctions):

Next #9). John is choosing a password for his access to the internet. He decided not to use the digit 0 or the letter M. Each letter or number may be used more than once. How many passwords of 2 letters followed by 4 digits are possible? So we have 6 positions to fill. 2 letters followed by 4 digits. Let's represent these positions with blanks. _ _ _ _ _ _ First let's fill the first two blanks with the two letters. A letter can be used more than once. However, the letter M is not allowed. Excluding the M, how many letters are in the Latin alphabet?

OpenStudy (anonymous):

26?

OpenStudy (anonymous):

25 i mean

OpenStudy (calculusfunctions):

Yes! OK so then since a letter may be repeated, how many ways are there of choosing two letters?

OpenStudy (anonymous):

25*2?

OpenStudy (calculusfunctions):

Is that 25 squared or 25 times two?

OpenStudy (anonymous):

Times 2

OpenStudy (calculusfunctions):

Wrong. If the first position can be filled with any of the 25 letters, then there are 25 ways of performing this first action. Now for the second letter, also any of the 25 letters can be used, hence there are 25 ways of performing this second action. Thus there are 25 X 25 ways of picking two letters. Understand?

OpenStudy (calculusfunctions):

25 X 25 = 625

OpenStudy (anonymous):

Nice work @calculusfunctions

OpenStudy (anonymous):

Oh i see now

OpenStudy (calculusfunctions):

Now let's look at the four digits. Excluding the digit 0, how many digits are in the decinary system?

OpenStudy (calculusfunctions):

Thank you @BarbaraKara . Back at ya!

OpenStudy (anonymous):

I dont know lol

OpenStudy (calculusfunctions):

How many digits do you use every day to represent an idea which is a number?

OpenStudy (anonymous):

100?

OpenStudy (calculusfunctions):

What?? What digits do you use? A digit is a symbol which consists of a single numeral. 100 is not a digit. It's a collection of symbols or numerals which expresses the an idea (what we cal a number).

OpenStudy (anonymous):

Im confused

OpenStudy (calculusfunctions):

Sorry, I don't mean to get philosophical. Please try again. How many digits are there in our decimal system?

OpenStudy (anonymous):

Like 1-9?

OpenStudy (anonymous):

1,2,3,4,5,6,7,8 or 9 ?

OpenStudy (calculusfunctions):

There are 10 digits. They are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9.

OpenStudy (calculusfunctions):

Now if you exclude the zero, then that leaves nine digits. Understand?

OpenStudy (anonymous):

Ok now im back to earth lol

OpenStudy (calculusfunctions):

Some we refer to our fingers as digits. You have 10 fingers, thus you have 10 digits.

OpenStudy (calculusfunctions):

OK so then if you use these nine digits, and a digit may be used more than once, how many four digit numbers are possible?

OpenStudy (anonymous):

9^2 times 4?

OpenStudy (calculusfunctions):

9 squared times 4? Incorrect. You mean 9 X 9 X 9 X 9 or 9 to the fourth power.

OpenStudy (anonymous):

so 6561?

OpenStudy (calculusfunctions):

So then 25 X 25 ways of placing the two letters and 9 X 9 X 9 X 9 ways of placing the four digits. Thus how many ways of placing the two letters and the four digits?

OpenStudy (calculusfunctions):

25 X 25 X 9 X 9 X 9 X 9 = ?

OpenStudy (anonymous):

4,100,625!

OpenStudy (calculusfunctions):

Yes that is correct!

OpenStudy (anonymous):

Alright cool

OpenStudy (calculusfunctions):

Alight now for the final question. #10). What is the probability of rolling a 2 on a die and then re-rolling the die and getting an even number? Fist what is the probability of rolling a 2 an a six-sided die?

OpenStudy (anonymous):

1/6

OpenStudy (calculusfunctions):

Yes and then what is the probability of rolling an even number with the same die?

OpenStudy (anonymous):

1/2

OpenStudy (calculusfunctions):

Yes so what do you get when you multiply these results?

OpenStudy (anonymous):

1/12

OpenStudy (calculusfunctions):

Correct! So the the correct answer is D). 3/36 = 1/12. You see they tried to trick you in that last question, by not reducing the fraction.

OpenStudy (anonymous):

Ahh i see it now, thanks so much for the help!

OpenStudy (calculusfunctions):

Welcome! Now I have to go. I think I burned the chicken nuggets.

OpenStudy (anonymous):

BAHAHHAHAAHA ^^

OpenStudy (anonymous):

LOL alright

OpenStudy (muscrat123):

@Macbass03

OpenStudy (anonymous):

@Chicken_Nuggets_ Do you go to Keystone Online? I had that EXACT same problem.

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