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Find the point on the terminal side of θ= -3pi/4 that has an x coordinate of -1. Show your work for full credit.
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equilateral triangle, both sides have length 1
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The (x,y) coordinates of points in polar form are (r cos(theta), r sin(theta)). Since we know the x coordinate of this point, we can use that to find r and then find the y coordinate using that value. \[x = r \cos(\theta)\] \[-1 = r \cos(-3 \pi / 4)\] \[-1 = r \times (- \sqrt2 / 2)\] \[r = \sqrt 2\] Now that we know r, we find y = r sin(theta). \[y = r \sin(\theta) = \sqrt 2 \times \sin(-3 \pi / 4) = -1\]
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