Question

I need help solving this problem for the given variable. The variable I need to solve for is a theta(the zero with the -in it). r= sqrt2A/theta

Answer 1

\[\large r=\frac{\sqrt{2A}}{\theta}\] like that?

Answer 2

the sqrt is over the entire fraction

Answer 3

or like this
\[\large r=\frac{\sqrt{2}A}{\theta}\]

Answer 4

oh like this
\[\large r=\sqrt{\frac{2A}{\theta}}\]

Answer 5

yes

Answer 6

square both sides first to get rid of the radical
then it will be easier
\[r^2=\frac{2A}{\theta}\]

Answer 7

can you finish it from there?

Answer 8

r^2=2A/{theta}

Answer 9

yeah that is the first step

Answer 10

multiply both sides by 2A? I am sorry, but it always takes me forever on these b/c I still find the entire process difficult.

Answer 11

At this point I have {theta} = 2A*r^2
The answer key has the answer listed as {theta}=2A/r^2

Answer 12

ok lets make it obvious

Answer 13

suppose \(r^2=9, A=18\) so \(2A=36\) and you had to solve
\[9=\frac{36}{\theta}\] what would you get?

Answer 14

in other words, what would you divide 36 by to get 9 ?

Answer 15

4
I get it. Thanks. This is why it takes me so long, I always make it more difficult.

Answer 16

lol good
so you see \(9=\frac{36}{\theta}\iff \theta =\frac{36}{9}\) and similarly \(r^2=\frac{2A}{\theta}\iff \theta =\frac{2A}{r^2}\)

Answer 17

btw if you ever get confused by these, you can always try it with numbers and see what you would do
sometimes all the letters get confusing

Answer 18

I will try that thanks!!