(6y2 -6/ 8y2 +8y)/(3y -3 / 4y2 + 4y) help please
@satellite73
Okay I have a little more time to help you out lol...
OK THANK YOU
|dw:1374858409390:dw| Like that??
yes sorry my internet shut down
Don't worry about it :) and that is exactly as it is written?
yes
Okay...so just like the last one...you flip the bottom fraction and turn this into multiplication.. \[\large \frac{ 6y^2 - 6 }{ 8y^2 + 8y } \times \frac{ 4y^2 + 4y }{ 3y - 3 }\] Now multiply across again...
9y^3-3=32y^4+32y^2
Actually you know what....is this a multiple choice question??
no
Oh okay...well I would actually just leave it as it....you can't really simplify anything after you set it up like this... \[\large \frac{ 6y^2 - 6 }{ 8y^2 + 8y } \times \frac{ 4y^2 + 4y }{ 3y - 3 }\] this equals... \[\large \frac{ (6y^2 - 6)(4y^2 + 4y) }{ (8y^2 + 8y)(3y - 3) }\] Like I said there's nothing really to simplify so I would leave it at this...if you want to multiply the top and the bottom out...go ahead but there's no reason to in my mind...
???????
Whats wrong?
im confused
With what part?
like just multply it out the divide or no
Well like I said....we can *I'll do it in a second for you* but....there is nothing to do after that to simplify...here let's see...
\[\large \frac{ (6y^2 - 6)(4y^2 + 4y) }{ (8y^2 + 8y)(3y - 3) }\] After multiplying it out we get... \[\large \frac{ 24y^4 + 24y^3 - 24y^2 - 24y }{ 24y^3 - 24y^2 + 24y^2 - 24y }\] I mean I guess if anything we could factor out a 24y from top and bottom... \[\large \frac{( y^3 + y^2 - y - 1) }{ (y^2 - 1) }\] And this (when divided out) become (y + 1) So I guess I was wrong...good thing you told me to multiply it out lol :) sorry about that...
so my answer is (y+1)
That is what I get! :)
ok what about this one\[\frac{ 1 }{ x-1 }+\frac{ 2 }{ x }=0\]
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