SOMEONE HELP PLEASE MEDAL REWARDED!!
@genius12 @Loser66 @satellite73 @SmoothMath @vinnv226
@e.mccormick
@Mr.ClayLordMath
Polys can't have negative or fractional exponents, which also eliminates roots.
it eliminates a,e and f?
Correction: Polly variables can't have....
what?
Well, the constant part can be any valid constant. But the variable (x, y, etc.) can't be the bottom of a fraction, have a fraction for an exponent, or have a negative exponent.
So \(x^2\) is good and so is \(\frac{1}{2}x^2\) , whichh means \(\frac{x^2}{2}\) is fine because that is just the 1/2 in disguise. However, these are all invalid as polys: \(x^{-2}\) \(\dfrac{1}{x}\) \(\sqrt[3]{x}\) \(x^{\frac{1}{2}}\)
A constant part, and just the constant part, is fine as a root. Why? Well, think about this: \(2=\sqrt{4}\) right? Well, \(x+2\) is a polynomial, which means \(x+\sqrt{4}\) is also a poly.
im still confused
OK, know what the constant and variables are references to? What I mean when I say constant or when I say variable?
the number nd the letter?
Basically... but there is a little more. In \(3x^2+7x-5\): 3, 7, and 5 are the constants and x is the variable. However, there are times like this: \(\pi r^2\) where \(\pi\) is the constant and r is the variable. So not just a number but also things that represent specific values.
\(e\), \(i\), \(\pi\), \(\sqrt{2}\) and many others that are not integers are constants.
So in a polynomial the constants can be any valid constants. Fractional constants, real constants, complex constants, and so on. The restrictions are on the variables. The variables can not: be in the bottom of a fraction, have a negative exponent, have a fractional exponent, or be inside a root.
b,d,e?
Missing one....
a?
Nope. That is a variable inside a root.
i think its f
constant inside a root: OK, variable: bad. Yes. F.
so the answer r are b,d,e,f?
Yep. b, d, e, f. a has a root in the wrong place. c has a negative exponent on a var. Sorry bout the confusion at the start. Oh, and you may wonder why \(x^2\) can be a poly when poly means many or multiple. It is logical why. See, \(x^2= x^2+0\) and therefore the invisible +0 makes any single term into a polynomial!
its ok and that was very helpful
Kk. Have fun!
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