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Algebra 21 Online
OpenStudy (anonymous):

Does anyone know how to figure out the following; 6x^3-14x^2+3x-7?

OpenStudy (compassionate):

Yes, we do. Would you happen to know the first step, hun?

OpenStudy (anonymous):

well I multiplied the 6*7 and came up with 42... but when I added 6+7 it does not equal 14.

OpenStudy (anonymous):

I don't know if i'm doing the right thing or if i'm missing a step.?.?

OpenStudy (compassionate):

6x^3-14x^2+3x-7? Exclude the 6x^3 -14x^2 + 3x - 7, just solve that.

OpenStudy (anonymous):

ok so I came up with 98, and when added came up with 21, which 3 is a common factor when multiplied with 7.

OpenStudy (compassionate):

\[6x^3-14x^2+3x-7\] You want to factor by grouping. 6x³ - 14x² + 3x - 7 = 2x²(3x - 7) + 1(3x - 7) = (2x² + 1)(3x - 7) We basically found a common denominator for 6 and 14, and the same for 3 and 7, then we factored it through.

OpenStudy (anonymous):

Thank you for the explanation... I appreciate it...

OpenStudy (compassionate):

I hope it helped. OpenStudy on ~~

OpenStudy (anonymous):

it did thx...

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