Question

simplify

Answer 1

whats the first step?

Answer 2

\[\frac{ 3 }{ x+1 } \times \frac{ x-1 }{ 5 }\]

Answer 3

i have no idea

Answer 4

times like this :)

Answer 5

Ugh I lost what I was writing, let me explain you the rules

Answer 6

First you need to know two things going into this problem, you can divide any number by 1 and it wont change that numbers value. Essentially every number can be expressed as a fraction

For example:
\[\frac{3}{1} =3\]

Secondly you can divide the top and the bottom of a fraction by any number and it wont change that fractions value.

For example:
\[\frac{3}{2} = \frac{3*2}{2*2} = \frac{6}{4}\]

The reason you flip the bottom fraction and multiply is because you want to turn the denominator into 1.

To explain look,

\[\frac{\frac{3}{x+1}}{\frac{5}{x-1}} = \frac{\frac{3}{x+1}*\frac{(x-1)}{5}}{\frac{5}{x-1}*\frac{x-1}{5}} = \frac{\frac{3(x-1)}{(x+1)5}}{\frac{(x-1)5}{(x-1)5}} = \frac{\frac{3(x-1)}{(x-1)5}}{1}\]

Answer 7

\[\frac{\frac{3(x-1)}{(x+1)5}}{1} = \frac{3(x-1)}{(x+1)5}\]

Answer 8

I hope you understand distributive law

Answer 9

Thanks