Question

Which of the following points is in the solution set of y < x2 - x - 6?

a) (-2, -1)
b) (0, -5)
c) (3, 0)

Answer 1

test one by one

Answer 2

I got (-2 -1) as the answer but I was just checking

Answer 3

well, let's test them, let's try A

y < x2 - x - 6
(-2, -1)

\(\bf -1 < (-2)^2-2-6 \implies -1 < -4\)

well, is that true?

Answer 4

anyhow, -1 is greater than -4, so no dice there
test B

Answer 5

(-2 -1) dont look right

Answer 6

ok ill try another one

Answer 7

darn it @timo86m is correct, I missed out on the signs, lemme redo that

Answer 8

\(\bf -1 < (-2)^2-(-2)-6 \)

Answer 9

which makes it -1 < 0

now is -1 < 0?

Answer 10

is it c

Answer 11

bc I got -5 < -6 for b

Answer 12

hmm, well, for b?
y < x2 - x - 6

(0, -5)

-5 < 0^2-0-6

-5 < -6

Answer 13

well, that's correct, however, keep in mind that for negative values, the farther you're from the zero, the smaller it gets
the close to the 0, the larger it gets

to -5 is greater than -6
but +5 is less than +6

Answer 14

so after fixing up my sign bit

now is -1 < 0

yes, thus is true, thus that's the point that checks out for the inequality

Answer 15

A)