Question

Given f(x) = 3x + 7, and g(x) = x − 1 ƒ(g(5)) =3x+32 right?

Answer 1

f(g(5)) should be a constant number

Answer 2

ie there shouldn't be any variables in the answer

Answer 3

what is the value of g(5)

Answer 4

19 dear :)

Answer 5

pengembara_bumi1 you're not helping anyone by just giving out answers

Answer 6

is it 62?

Answer 7

g(x) = x − 1

g(5) = 5 − 1 ... replace every x with 5

g(5) = ???

Answer 8

4

Answer 9

now that we know that g(5) = 4, we can use this to find f(g(5))

Answer 10

22 for f?

Answer 11

f(x) = 3x + 7

f(g(x)) = 3( g(x) ) + 7 ... replace every x with g(x)

f(g(5)) = 3( g(5) ) + 7 ... replace every x with 5

f(g(5)) = 3( 4 ) + 7 ... replace g(5) with 4 (since we just found that g(5) = 4)

f(g(5)) = 12 + 7

f(g(5)) = 19

Answer 12

fg(x)=? when x=5
g(5)=5-1
g(5)=4
f(4)=3(4)+7
fg(5)=19

Answer 13

hopefully all that makes sense

Answer 14

sorry @jim_thompson5910 :(

Answer 15

its fine, just keep it in mind

Answer 16

thank you!!! both of you!!!!

Answer 17

you're welcome