Select the inequality that corresponds to the given graph. 4x - 3y > - 12 x + 4y > 4 4x - 2y < - 8 2x + 4y greater than or equal to - 16
Post the graph.
okay, what's the equation of that line?
Would it be (-2,3)
Well there is a point (-2;0) and a point (0,4). Use those points to figure out the slope.
I would use y=mx+b to find the slope right?
Yea, you could do that.
So would the answer by a slope of 4?
Can you post your calculations here? (The slope is not 4, and you're nowhere near the answer yet).
I'm confused? Can you please walk me through on how to find the slope, I don't expect you to just give me the answer i really want to learn how to find the slope and be able to understand this stuff?
Well, slope in your equation is M = difference in y / difference in x To find the slope you would take two points, say: (x1; y1), and (x2;y2) and M would be:\[M = \frac{y_2-y_1}{x_2-x_1}\]
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Yes. You can also think about it in terms of rise/run (how much the graph went up by (or down) divided by how much it went to the right (or left). Like this:
Doesn't matter what points you pick, as long as they're on the line. I picked the ones that were easy to calculate.
so the rise is 2 and the run is 1
Yes, and the slope is?
wait i don't understand the slope is positive right? So how could it be -16?
Ok, which two points did you pick to find the slope?
-2,0
That's only one point: (-2,0) -> (x,y).
okay so i used (-2,0) and (4,0) and then i subtracted 4- -2 and i got 6?
(4,0) is not on that line. Keep in mind, the order is: (x,y)
(0,3) is on the line right?
take a look at what's on the line, stop guessing.
I didn't guess isn't 0 on the x axis and 3 on t y axis? I am honestly really trying
It needs to be right on top of that dashed line.
what do you mean by on top of the line?
Hang on, I'll draw some.
sorry:/
The red ones are on that dashed line. The blue ones are not.
so my two pints could be (-2,0) and (-2,4)?
points
mark (-2,4) in the graph you showed me.
-2 is on the x axis and 4 is on the y axis
But where is the point itself: (-2;4) Is that point on the line?
Yes
No! sorry, i understand you now
(-2,-2)
(-2, -2) is on the dashed line?
No i didn't mean -2... (-2,1)
You need to watch this: http://www.virtualnerd.com/algebra-1/relations-functions/coordinate-plane/coordinate-plane-graphing/coordinate-plane-graph-points-example
Use the point-slope formula for this question( \[y=mx+b\] ). Note that M is the slope or rise over run. \[Rise/Run\] Therefore, we already have point (-2,0) and a point (0,4) and with these points we have, we can figure out the slope. Rise/Run or 4/2 Which equals 4 When x=0 the y-value line hits the y-axis, you can notice that B (y-intercept) is 4. So \[y=mx+b\] you plug in the numbers and u get y=2x+4 From your graph, the dividing line is a dash line. Solid line is greater than or less than and the dash line is greater than/less than or equal to. 2x+4 is less than the y shaded area. The area above is shaded (because y is greater than 2x+4) Soooooo the answer is y>2x+4 someone correct me if i had did something wrong
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