please help @Falco276 @jim_thompson5910 @dumbcow
this is the question please
You know what those operators \(\cup\) and \(\cap\) mean?
no
addition and multiplication??
They mean union and intersection, respectively. Union is *similar* to addition while intersection means 'elements in common'
ok.so can you help me answer those questions
Here's an example... X = {1,2,3,4,5,6,7} Y = {2,4,6,8,10} The union of X and Y would be all their elements, together... \[X\cup Y = \left\{1,2,3,4,5,6,7,8,10\right\}\] But their intersection would be only the elements that they share... \[X \cap Y = \left\{2,4,6\right\}\]
yes i know that but i have a problem with the question i posted thats why i need help
Let's try the first one, \(A \cup B\) So, what do A and B correspond to?
all the elements in A ND B
That's right. And you know how many elements there are in A and in B...so what do you do to them to get the *union*?
WRITE THEM ALL OUT
No... you're not asked to write out the elements, you're just asked HOW MANY elements are in the union...
And easy on the caps lock, mate :)
lol
oh ok.so i write 4?
Why 4?
cos group A has 2 likewise B
OR NO I ADD THEM ALL UP
How do you figure that group A has 2?
i have changed my mind,i need to add the elements in A up and the same for B
And you get...?
138137
That's right :)
YAY..THEN TO B
Now the second one.... is trickier... You have to do them one at a time... So... \[\Large E\cap (C\cup D)\]
So, this part\[\Large E\cap \color{blue}{(C\cup D)}\]means the elements in C or D, like in part (a). However, this part here \[\Large \color{red}{E\cap} (C\cup D)\] Means you only take the elements in C or D *that are also in E* Or in other words, only Marines and Navy-units that are ENLISTED. (no officers)
Ok so what is the answer.
You lost me there :P
LOL Just kidding. That red part there only means you add the parts that are in the (E) row \[\Large \color{red}{E\cap} (C\cup D)\]
so u mean the answer is 52448
That is correct :P
den the next questiion
Now to (c) I missed introducing that prime \(\prime\) operator. It simply means "not" so O' means "not in O" and B' means "not in B"
oh ok
therefore...lol
Well, what does it mean, to 'not be in O'
then in E
Correct. So only count the ones in E. Now, what does it mean to not be in B?
IN A C ND D
Good, so, now you take the intersection. You want those in E, but also in either A, C, or D. Add them up.
so with those in E i need not add B in it
Yup, that's another way to look at it :)
did u say i needed to find the intersection
Intersection, yes. So that just means elements in E *and* in B' (which means not in B)
so i would have O prime as 57825,42400.10049
Yup... that's actually already O' \(\cap\) B'
and B prime as ??
oh so that is the answer
No, O' is all of E. (B included) But since you intersected it with B', then you have to take away the B.
so im right on that one?
Depends... what's your answer?
i need to add all of them up or
Yup.
110274
so with union and intersection i need to add up every time
Yes, with union, you simply add all the concerned, while with intersections, you need to do a little more thinking. Mind you, this is a rather simple example, normally, taking unions/intersections isn't nearly as straightforward as this one...
oh ok.
i have another question
Yes?
let me tag you in it then
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