Question

You roll 2 dice. What is the probability that the sum of the dice is odd or 1 die shows a 5? A 6 X 6 table of dice outcomes will help you to answer this question.

Answer 1

@mary.rojas

Answer 2

@ybarrap

Answer 3

@genius12

Answer 4

hope this helps:
This is a basic problem:

The sum of numbers can be either even or odd....
The probability of having a sum as odd is 1/2.

Probability of none of the dices showing a four is (5/6)*(5/6) = 25/36
Thus probability of at least one four is 1 - 25/36 = 11/36

Total probability = 1/2 + 11/36 = 29/36

Answer 5

yeah that's what we did earlier...

Answer 6

@bahrom7893 help?

Answer 7

so thats not it?

Answer 8

so I got the pairs:
2,5
5,2
6,5
5,6

Answer 9

1, 2
1, 4
1, 6
2, 1 (disregard)
2, 3
2, 5
3, 2 (disregard)
3, 4
3, 6
4, 1
4, 3 (disregard)
4, 5
5, 2 (disregard)
5, 4 (disregard)
5, 6
6, 1 (disregard)
6, 3 (disregard)
6, 5 (disregard)

Those are the ones with an odd sum.

Answer 10

ok

Answer 11

but not all of them show a 5 like it asks u to

Answer 12

I disregarded the ones that were repeated. And I'm not done yet.

Answer 13

1 die shows a 5:
1,5
2,5 (disregard)
3,5
4,5 (disregard)
5,5
6,5 (disregard)

Answer 14

So we have:
13/36 possible outcomes

Answer 15

ok now w/out typing "DISREGARD" for some, can u list all the pairs that would go w/ this problem?

Answer 16

ill start off and u can add any if I miss them

Answer 17

2,5
5,2
6,5
5,6

Answer 18

1, 2
1, 4
1, 6
2, 3
2, 5
3, 4
3, 6
4, 1
4, 5
5, 6
1, 5
3, 5
5, 5

Answer 19

oh it says OR huh?

Answer 20

that why I only listed a few.... my bad

Answer 21

Yea, so you add the possible outcomes.

Answer 22

ok so that's the whole list??

Answer 23

im pretty sure it is.

Answer 24

so there's 13...

Answer 25

so 13/36 ???

Answer 26

There's probably a smarter way of doing this, but i think so.

Answer 27

It's late, and I'm tired after work. Someone should check this over.

Answer 28

yea thanks bahrom. @oldrin.bataku can u pls check this???

Answer 29

THE ANSWER WAS WRONG!!!!!!! D: D:

Answer 30

Sorry.. hopefully oldrin will sort things out. I'm falling asleep here.

Answer 31

AND WE HAVE A WINNER!

Answer 32

The easiest method is just to write out all the possible sums: