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Mathematics 7 Online
OpenStudy (anonymous):

You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, then without putting it back you draw a random second card from the ones that are left. Use a tree diagram to calculate the probability that you draw exactly 1 jack. A. 4/9 B. 2/9 C. 2/6 D. 2/3 E. 1/3

OpenStudy (anonymous):

@terenzreignz

OpenStudy (kropot72):

|dw:1374900723246:dw| Out of the six possible outcomes, how many have one Jack?

OpenStudy (kropot72):

The six possible outcomes are: KQ, KJ, QK, QJ, JK and JQ.

OpenStudy (kropot72):

@music101 Are you there?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@genius12

OpenStudy (anonymous):

@Loser66

OpenStudy (loser66):

that means you have only 3 cards: K , Q and J?

OpenStudy (anonymous):

yes its a 3-card deck

OpenStudy (anonymous):

So, first pick up there is a 1/3... second there is a 1/2 and last pick up there is exactly a 100% chance. Exactly 1 jack is 1/3..

OpenStudy (loser66):

yep, agree.

OpenStudy (anonymous):

really? someone else said that it was 4/9??

OpenStudy (loser66):

That's why I want to make sure about the problem. Depend on how many cards you have, the probability count on it. You said that you have only 3 different cards, so the answer is 1/3. If you said you have 12 cards: 4K, 4Q, 4J, the answer is different!!

OpenStudy (anonymous):

well u can re-read the problem above to make sure

OpenStudy (loser66):

or if you have a whole set of a deck unless 3cards 1K, 1Q ,1J. The answer is another number.

OpenStudy (loser66):

ok, to me, 1/3 is ok.

OpenStudy (anonymous):

ok.. im gonna submit it then

OpenStudy (kropot72):

There are four outcomes where one Jack was drawn. Therefore the probability of one Jack is\[P(one\ Jack)=\frac{4}{6}=\frac{2}{3}\]

OpenStudy (anonymous):

@kropot72 There are only 3 cards in the deck... Each time you take a card you can't replace it....

OpenStudy (kropot72):

@mebs If you look at the tree diagram you will see that there is no replacement of the first card that is drawn.

OpenStudy (anonymous):

So... @kropot72 if we wanted the jack at the first try wouldn't there be a 1/3 chance only..?

OpenStudy (anonymous):

Yes... I see your argument.. if you don't get exactly 1 jack at the first attempt than you have the second and third... which Is 2/3.. but didn't they want it at the first attempt.?@kropot72

OpenStudy (kropot72):

The question states that there are two draws. There are two draws, regardless of whether or not a jack is drawn on the first draw. Look at the tree diagram that I have posted.

OpenStudy (anonymous):

Yes you are correct the answer is 2/3... haha should have read it more carefully.... try calling music101 and tell her..@kropot72

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