You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, then without putting it back you draw a random second card from the ones that are left. Use a tree diagram to calculate the probability that you draw exactly 1 jack. A. 4/9 B. 2/9 C. 2/6 D. 2/3 E. 1/3
@terenzreignz
|dw:1374900723246:dw| Out of the six possible outcomes, how many have one Jack?
The six possible outcomes are: KQ, KJ, QK, QJ, JK and JQ.
@music101 Are you there?
yes
@genius12
@Loser66
that means you have only 3 cards: K , Q and J?
yes its a 3-card deck
So, first pick up there is a 1/3... second there is a 1/2 and last pick up there is exactly a 100% chance. Exactly 1 jack is 1/3..
yep, agree.
really? someone else said that it was 4/9??
That's why I want to make sure about the problem. Depend on how many cards you have, the probability count on it. You said that you have only 3 different cards, so the answer is 1/3. If you said you have 12 cards: 4K, 4Q, 4J, the answer is different!!
well u can re-read the problem above to make sure
or if you have a whole set of a deck unless 3cards 1K, 1Q ,1J. The answer is another number.
ok, to me, 1/3 is ok.
ok.. im gonna submit it then
There are four outcomes where one Jack was drawn. Therefore the probability of one Jack is\[P(one\ Jack)=\frac{4}{6}=\frac{2}{3}\]
@kropot72 There are only 3 cards in the deck... Each time you take a card you can't replace it....
@mebs If you look at the tree diagram you will see that there is no replacement of the first card that is drawn.
So... @kropot72 if we wanted the jack at the first try wouldn't there be a 1/3 chance only..?
Yes... I see your argument.. if you don't get exactly 1 jack at the first attempt than you have the second and third... which Is 2/3.. but didn't they want it at the first attempt.?@kropot72
The question states that there are two draws. There are two draws, regardless of whether or not a jack is drawn on the first draw. Look at the tree diagram that I have posted.
Yes you are correct the answer is 2/3... haha should have read it more carefully.... try calling music101 and tell her..@kropot72
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