Question

For Two Concentric Spherical shells having radii "a" and "b" s.t a 12 years ago

Answer 1

if you have prolem ..then see
then

so now i think you can again try to solve it.....and dielectric is jus changes the value of epsilon..so dun wry...:)

Answer 2

RaGhavy I think the question I have I asked deals with the effect of Dielectric on the flux---I mean I am confused whether the medium Outside or medium inside has an effect on the flux...I am sorry I could not correlate ur answer wid my question...

Answer 3

let in the figure ,the medium inside A is air with charge,,,,and b/w A and B is a medium of di-electric const. K..

now its easier to find the flux thru A..now we find the flux thru B..
for that we know that flux thru C and D in the fig. below are the same..and is q/epsilon
now consider no charge b/w A and B
so the flux thru B wud have been the same,,if there was no charge and media other than air in b/w A and B..
now ..imagine there was no charge in A..and only di-electric with the charge be there b/w A and B..so then also one can find out theflux thru B,,that wud b..q/K(Epsilon)... because gauss law doesnot take into account the position of charge inside the object...now combine all of that and u should get your answer...if not,tell me your part of the solution and i will help to correct the mistake..

Answer 4

ok...RaGhavi...I am trying my answer but not sure right or wrong.I simply take flux as \[\Phi= Q/k \epsilon 0\]
where K= dielectric constant of the medium just outside the shell.
This way \[\phi 1 =q / K2 \epsilon 0\]
and \[\phi 2 = Q+q / \epsilon 0\] and are totally independent of the radii :)

Answer 5

tell how you get on to the (phi)2..the second flux..??

Answer 6

Simply by applying Gauss's Law