Question

(i)^58

Answer 1

@fabo What's your question?

Answer 2

simplify

Answer 3

Could you post the question?
it just says
\[(i)\ ^{58}\]

Answer 4

Sorry I get it, i the root of -1. Do you know what's \(i^4\)

Answer 5

no I dont how to to do it

Answer 6

ok you know what's i?

Answer 7

yes a cpmplex number

Answer 8

yes, right \[i=\sqrt{-1}\]
so
\[i^2=???\]

Answer 9

we know i^58=(i^2)^29 ..so since i=root(-1) i^2 should be -1..so i^58=(-1)^29=-1

Answer 10

(i)^58

= (i^2)^5 * (i^2)^4 * (i^2)^3 * i^2

= (-1)^5 * (-1)^4 * (-1)^3 *-1

= -1 * 1 *-1 *-1

= -1 * 1

= -1