Question

Please help with this problem?
the range of a projectile fired at an angle θ with the horizontal and with the initial velocity of v0 feet per second is r=1/32v0^2 sin2θ where r is measured in feet. A golfer strikes a golfball at 115 feet per second. Ignoring the effects of air resistance, at what angle must the golfer hit the ball so that it travels 160 feet?

Answer 1

11.55 degrees

Answer 2

if taken 9.8 as g else if ten then it will be 12

Answer 3

@harpreetsk
ANSWER CHOICES:
23 degrees
11 degrees
17 degrees
7 degrees
26 degrees

Answer 4

11 is correct then it would be result if taken g as 9.62

Answer 5

ok thanks

Answer 6

the way to do this is put in the numbers they give you into the equation
\[ r=\frac{v_0^2}{32} \sin2θ \]
r , the distance is 160 ft
the velocity V0 is 115
\[ 160=\frac{115^2}{32} \sin2θ \]
multiply both sides by the inverse (flipped fraction)
\[ 160 \cdot \frac{32}{115^2} = \sin 2\theta \]

you will need a calculator to find the inverse sin of both sides
that will give you 2θ
divide by 2 to get θ