Question

solve the following equation: I get stuck every time.

Answer 1

\[-dsin35.0 = -\frac{ 1 }{ 2 }g \left( \frac{ dcos35.o }{ 25m/s} \right)^{2}\]

Answer 2

we are solving for d @Festinger

Answer 3

You need to distribute the square so you get:\[-d \sin 35=-\frac{ 1 }{ 2 }g \frac{ d ^{2}\cos ^{2} 35}{ 25^{2}\frac{ m ^{2} }{ s ^{2} } }\]The divide "d" from both sides:\[-\sin 35=-\frac{ 1 }{ 2 }gd \frac{ \cos ^{2}35 }{ 25^{2}\frac{ m ^{2} }{ s ^{2} } }\]Then you leave "d" alone on the left side and you get:\[d=-2\frac{ 25^{2}\frac{ m ^{2} }{ s ^{2} } \tan 35 }{g \cos 35 }\]

Answer 4

thank u!

Answer 5

@ivancsc1996 i thought \[\cos^2\theta = 1-\sin^2\theta\] but here you used \[\cos^2\theta = \cos \theta \times \cos \theta\]

Answer 6

Both are the same.

Answer 7

ok thx :) i didnt knw the second

Answer 8

:)