Question

solve the following equation:

Answer 1

\[-dsin35= -\frac{ 1 }{ 2 }9.81 \left( \frac{ dcos35 }{ 25 } \right)^{2}\]

Answer 2

Solving for \(d\), I'm assuming?
\[-d\sin25^\circ=-\frac{1}{2}(9.81)\left(\frac{d\cos35^\circ}{25}\right)^2\\
d\sin25^\circ=4.905\left(\frac{d^2\cos^235^\circ}{625}\right)\\
0.4226d=0.0053 d^2\\
d^2-79.7358d=0\\
d(d-79.7358)=0\\
~~~~~~~~~~~~~~~~\vdots \]

Answer 3

d should be 109.. how did you get rid cos^2?