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what is lim h tends to 0 hcos(1/h) ?
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This has no definite limit. It goes to infinity.
but why?
cos(1/0) has any value between -1 to 1 no? then any value between -1 to 1 * 0 should equal to 0 no?
yes you are right cos(infinity) have value between -1 and 1 so its 0
so \[\lim h \rightarrow0 hcos1/h \] will be 0 na?
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yup \[\lim(hcos(\frac{ 1 }{ h }))\] when h->0 is 0
thanks :-)
no problem
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