Question

The figure below shows CB = 4, BE = 5, AB = x - 4, and DB = x + 3.

If â–³ABC ~ â–³DBE, the value of x is _________

Answer 1

@AwesomeB

Answer 2

I think it's 7, but I think I'm wrong.

Answer 3

?

Answer 4

In \[\Delta ACB - and -\Delta DEB \]
\[\angle C \cong \angle E - (each - 90^0)\]
\[\angle B \cong \angle B - (common-\angle)\]
therefore ΔACB ~ ΔDEB ( By A-A) property
Therefore
\[\frac{AB}{DB}=\frac{CB}{EB} \rightarrow \frac{x-4}{x+3}=\frac{4}{5} \rightarrow 5x-20=4x+12\]
5x-4x=20+12
x=32

Answer 5

Thank you. (:

Answer 6

You are most welcome

Answer 7

:D