Question

Choose the product.
-7p 3(4p 2 + 3p - 1)
A:-28p5- 21p4+ 7p3
B:28p6+ 21p3- 7p
C:21p3+ 8p2+ 3p4- 8p
D:-21p5+ 8p4- 3p3

Answer 1

Is this the full question?

Answer 2

I'm guessing that the first line is the question and the rest are the answers?

Answer 3

\(-7p^3(4p^2+3p-1)\)
Is that what the questions looks like?

Answer 4

yeah sorry

Answer 5

The answer is C

Answer 6

No problem. You can use the Equation button to help you write equations in the future.

So, what is the question? Do you know how to multiply numbers with exponents?

Answer 7

D

Answer 8

The answer is D sorry

Answer 9

Wait, a second

Answer 10

nope plz explain

Answer 11

Just give me a moment before a make a mistake let me check

Answer 12

Oh the 3 was raised to the power

Answer 13

Ok. You will distribute the \(-7p^3\). The first multiplication will be \(-7p^3 \times 4p^2\).
Start by multiplying the coefficients.

Answer 14

Answer is A by the way

Answer 15

While you are explaining can you verify if I am correct, thanks

Answer 16

Then, multiply the variable. \(p^3 = p \times p \times p\) and \(p^2 = p \times p\) so, \(p^3 \times p^2 = p^5\). In other words, when multiplying - add the exponents.

Answer 17

Does that make sense?

Answer 18

uhh can you show everthing you did to the equation i kinda slow

Answer 19

OK. Starting from the beginning.
Do you understand how to distribute?

Answer 20

i think so- 28p^5+-21p+-7p

Answer 21

Almost. Consider this:
\(-7p^3(4p^2+3p-1)\) = \(-7p^3 \times 4p^2 + -7p^3 \times 3p -1 \times -7p^3\)

Answer 22

Do the multiplication first. Do you understand how \(-7p^3 \times 4p@ = -28p^5\)?

Answer 23

\(-7p^3 \times 4p^2 = -28p^5\)

Answer 24

-28^4+-21p+7p^2?

Answer 25

I'm not sure what you are doing to get that answer. I can guide you through this problem, but you will need to answer my questions so I can help you.

Answer 26

ok

Answer 27

Do you understand the distribution?
(-7p^3 \times 4p^2 + -7p^3 \times 3p -1 \times -7p^3\)

Answer 28

\(-7p^3 \times 4p^2 + -7p^3 \times 3p -1 \times -7p^3\)

Answer 29

im sorry the exponent 3's you were using looked like 2's

Answer 30

\(\huge{-7p^3 \times 4p^2 + -7p^3 \times 3p -1 \times -7p^3}\)
Is that more clear?

Answer 31

-28p^3-21p^3 x 3p -1 x -7p^3

-49p^3 x3p-1 x -7p^3 good so far?

Answer 32

The small type can be difficult to read on smaller screens.
Let's start with the first multiplication:
\(\huge{-7p^3 \times 4p^2}\)

Answer 33

Yes. Now move on to the next multiplication.

Answer 34

-21p^3

Answer 35

\(\huge{-7p^3 \times 3p}\)
remember that when an exponent is not written, it is understood to be 1.

Answer 36

-21p

Answer 37

What about the exponent?

Answer 38

-21p^4

Answer 39

Yes. And the last multiplication?

Answer 40

7p^4?

Answer 41

Why an exponent of 4?

Answer 42

because -1 has an exponent of 1?

Answer 43

That is true, but the -1 term has no variable. You only add the exponents when the base is the same.

Answer 44

oh so u multiply them 7p^3

Answer 45

Yes. Now string them all together.

Answer 46

-28p5- 21p4+ 7p3, thank you that was'nt so hard after all

Answer 47

Everything is easy after you learn how to do it. :-)
Would you like to do another similar problem to make sure you understand it?

Answer 48

ok

Answer 49

\[\huge{4x^2(3x^4+2x^3-6x^2+5x-2})\]

Answer 50

12x^8+8x^6-24x^4+20x^2-8x^2

Answer 51

20x^14-24x^4+20x^2-8x^2

Answer 52

-4x^10+20x^2-8x^2

Answer 53

Did you distribute? Then multiply each term individually? None should be combined.

Answer 54

You were closest on your first attempt.

Answer 55

idk my head hurts

Answer 56

With your first answer, you were almost correct. You multiplied the exponents instead of adding them.

Answer 57

\(\huge{4x^2 \times 3x^4 = (3\times 4)x^{2+4} = 12x^6}\)

Answer 58

If the rules are difficult to remember, just expand it out:
\(\huge{x^4 \times x^2 = (x \times x \times x \times x) \times (x\times x)}\)
\(\huge{ = x\times x \times x \times x\times x\times x} = x^6\)

Answer 59

12x^6 +8x^5-24^4+9x^3-8x2?

Answer 60

Almost perfect. \(4 \times 5 = 20\) but your exponents are correct.

Answer 61

x^23?

Answer 62

It seems like you understand this now, do you want to do another shorter problem to make sure?

Answer 63

nah im good but if i close this question can i still veiw this,and can you awnswer another question for me?

Answer 64

Sure. and here is some interesting reading on the topic:
http://www.uhv.edu/ac/mathsci/pdf/exponents.pdf

Answer 65

thank you

Answer 66

Your Welcome.