Factor 360t + 10t ^3 - 120t ^2.
First, let me rewrite it to make sure I understand... \(\huge{360t + 10t^3 - 120t^2}\) Is there supposed to be an exponent on the first term?
360t + 10t³ - 120t² 10t(36 + t² - 12t) 10t(t² - 12t + 36) 10t(t - 6)²
the equation is correct
Would you like me to explain xoya's answer?
LOL
lolollooollololololololololololololo ok
It's just you have to take common first Here 10t is common :D
First step is to factor out the largest common term you can find. It keeps the numbers smaller and easier to work with.
Lol xD
@xoya, you are laughing, but in my experience, students learn better when they have to do the work themselves.
i can laugh like mr.crabs argh argh argh argh argh
I'm not familiar with mr. crabs - is that an evil laugh??? or a pirate laugh???
its a pirate laugh off of spongebob
Cute. :-) On a more serious note...do you understand how to factor?
no
\(\huge{360t + 10t^3 - 120t^2}\) My first step would be to rewrite the expression in descending order like this: \(\huge{10t^3 - 120t^2+360t}\) Simply because I like routine.
And consistency.
FRom there, factor out the largest common term you can find. The largest factor cannot be larger than the smallest coefficient, so start with 10.
im sorry my head hurts too much im taking a break
That will leave you with: \(\huge{10t(t^2-12t+36)}\) From there, you need to factor the trinomial.
Here is a good resource for when you return: http://www.mathwarehouse.com/algebra/factor/how-to-factor-trinomials-step-by-step.php
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