Use fundamental identities to simplify the expression below and then determine which of the following is NOT equivalent cotβsecβ answer choices: 1/sinβ secβ/tanβ 1/(cosβtanβ) secβ cscβ
I know the answer is not cscβ
well, cot = cos/sin and , sec = 1/cos so multiply them :)
\(\bf \cfrac{\cancel{cos(x)}}{sin(x)}\cfrac{1}{\cancel{cos(x)}}\)
If \(\csc\beta\) isn't an answer, then you also know that \(\dfrac{1}{\sin\beta}\) isn't an answer, either.
secβ/tanβ then?
Nope,\[\cot\beta\sec\beta=\frac{1}{\tan\beta}{\sec\beta}=\frac{\sec\beta}{\tan\beta}\]
ok then 1/(cosβtanβ)? because secβ is actually in the problem
If you rewrite the secant in my last comment, you'll see that they're the same: \[\frac{\sec\beta}{\tan\beta}=\frac{\frac{1}{\cos\beta}}{\tan\beta}=\frac{1}{\cos\beta\tan\beta}\] So you've eliminated four of the answers, meaning the right answer is...
ha ok secβ, sorry for my stupidity but thanks for help!
You're welcome!
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