For Josh's science project he is filling a mountain with fake lava liquid. The mountain he created was in the shape of a square pyramid with a base length of 12 inches. If 432 square inches of liquid fits into the pyramid, what is the pyramids height ???
Hi! Do you have any idea where to start?
nope
Alright! Well here's the thing:|dw:1374963754287:dw|You know the base length, and how much the volume is.
|dw:1374963857904:dw|
volume is 432 ?
The formula for the volume of a square pyramid is \(V=\frac{1}{3}b^2\ h\), as I found online. http://formulas.tutorvista.com/math/volume-of-a-square-pyramid-formula.html Yep, volume is 432, and it should be in cubic inches, not square inches.
\(b\) is the base length \(h\) is the height \(V\) is the volume. So you solve for \(h\)! Can you take care of the rest, then? I'll hang here, to double-check your answer and answer any questions you might have.
so.. 432=1/3(12)^2
what would i do next multiply 1/3 and 12^2
\[432\ [in^3]=\frac{1}{3}(12\ [in])^2\ h\]
You just forgot the \(h\), is all. And that's what you need to solve for. How are you with algebra?
im good i guess
Alright, so you have\[V=\frac{1}{3}b^2\ h\]What first, to get at \(h\) alone?
well to undo the division you multiply
Alright! If you want to tell me what to do, I'll change the formula for you. So multiply by \(3\), I think you're saying. \[\frac{V}{3}=\frac{1\times\cancel 3}{\cancel 3}b^2\ h=b^2\ h\]\[\qquad\Downarrow\]\[\frac{V}{3}=b^2\ h\]Now?
then you can go ahead and do 12^2
Okay!\[\frac{V}{3}=b^2\ h=(12)^2\ h=144\ h\]\[\qquad\Downarrow\]\[\frac{V}{3}=144\ h\]
wait 432/3 is 144 so 144=144 is 1 ?
Yeah, \(1=h\)! I guess that's your answer!
|dw:1374965054826:dw|\(\huge\color{blue}{\large\ \ o\ o\ \\\smile}\)
let mee see if its right
Okay.
its not ? :( the answer isnt 1
Are there different options for different units?
Or are you required to put in the units?
Oh gosh, I did it wrong, sorry.
That was my fault. \[3\times V=144\ h\]
ok
Yielding \(9=h\). I'm sorry.
and what unit do i put
square inches
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