The average height of an apple tree is 4.00 meters. How long would it take an apple falling from that height to reach the ground? Given: g = -9.8 meters/second^2 -0.82 Seconds -1.0 Seconds -1.53 Seconds -2.3 Seconds
Hi! You need an equation for this, do you agree? It has to have distance and acceleration! Any ideas?
Yes. I have none at all lol
\(d=v_it+\frac{1}{2}a\ t^2\) should suffice!
Wait...
What? lol And what does the varables symbolize in the equation? Well, I know V, but what's D, A, and T?
Well, \(v_i=0\)
\(d\) is the distance, or the height \(a\) is the acceleration. Here, it's the acceleration due to gravity, which is usually \(9.8\), \(9.81\), or \(10\ m/s^2\) depending on your teacher. \(t\) is the time, how long it will take the apple to fall.
The equations is now \(d=\frac{1}{2}a\ t^2\).
The whole thing is\[x_f=x_i+v_i\ t+\frac{1}{2}a\ t^2\] The "\(_i\)" indicates "initial," and the "\(_f\)" indicates "final." They're initial and final properties across the interval. Here, the interval is the apple being on the tree to where the apple hits the ground.
And \(a\) for you is \(-9.8\ [m/s^2]\).
So you've found the answer? :) Or do you have any questions?
I don't see a choice for the answer I got.
Actually, to be honest, I guessed and got it wrong :/ I'm only taking physics (trying to get at least a B) to get by and graduate with honors. But thanks anyways! For some reason, I'm just not understanding some criteria in Physics as greatly as I wish I could, especially since I'm self-teaching myself online -_- Again, thanks, theEric!
Lol I get frustrated easily with things like this.
Oh gosh! Self teaching! Good luck! Did it give you the correct answer?
I got\[\sqrt{\frac{(2)(-4\ [m])}{-9.8\ [m/s^2]}}\]
\(\approx 0.903508\ [s]\)
Thank you! :) I randomly clicked 0.82 and got it right.
Haha, nice! And I hope OpenStudy can help you out in the future :)
Take care!
Thank you very much! You take care too :] Thanks for your time and effort.
My pleasure, thanks.
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