Question

Find the factors of 3a^2 + 14a − 24.

(3a − 6)(a + 4)

(3a − 4)(a + 6)

(3a − 2)(a + 12)

(3a + 2)(a − 12)

i got the first option

Answer 1

How did you get that?

Answer 2

Hmm. Not quite, if you do the FOIL method on a, then it would give you something other than 3a^2 + 14a − 24.

Answer 3

I'm 12, and I only learned the basic way of factoring a trinomial. So if it was me doing that problem, I would guess and check.
Though, I'm sure other people knows how to do it, properly. :)

Answer 4

if you need to know the true answer you must check

Answer 5

14a

Answer 6

\[3a ^{2} + 14a − 24. \]
\[3a ^{2} +18a -4a − 24. \]
\[3a(a+6) -4(a+6)\]
(3a-4) (a+6)

Answer 7

18a-4a=14a which one give you this solution?????

Answer 8

I got B

Answer 9

If you do the FOIL method on b, then that would certainly give you 3a^2 + 14a − 24.
Good job, @FilthyMcNasty :)

Answer 10

xD

Answer 11

@sylinan, you understand how i got B?

Answer 12

Yes, No, Maybe so?

Answer 13

yes (:

Answer 14

yes (:

Answer 15

Hmm. Teach me. c:
I know that 18a - 4a = 14a.
But how did you know which number to use?

Answer 16

\[3a ^{2}+14a−24.\] (you multiply the 1st and Last terms) so 3a^2*-24 = -72a^2
- So u find 2 terms whose product is -72a^2 & add up to 14a

Answer 17

Ah. I see. Thanks! :)

Answer 18

3a²+14a−24.
(you multiply the 1st and Last terms)
so 3a²*-24 = -72a²
- So u find 2 terms whose product is -72a² & add up to 14a

Answer 19

If that's more legible , so yeah!