please help!
find the exact solutions of the given equation in the interval [0,2pi)
sin^2x+sin2x=-cos^2x+1

Question

please help!
find the exact solutions of the given equation in the interval [0,2pi)
sin^2x+sin2x=-cos^2x+1

anonymous · Answer

add $\cos^2(x)$ to both sides and then note that $\sin^2(x)+\cos^2(x)=1$ greatly simplifying the equation

anonymous · Answer

i take it the original equation is 
$$\sin^2(x)+\sin(2x)=-\cos^2(x)+1$$ right?

primeralph · Answer

Either way, your first step is right. @satellite73

anonymous · Answer

yeah thats the equation

anonymous · Answer

thank you @$\large' ralph$

primeralph · Answer

You remembered.

primeralph · Answer

@ginger994
Do you know what to do next?

anonymous · Answer

yeah i know the gist of it, thanks

anonymous · Answer

you should end up with 
$$1+\sin(2x)=1$$ as a second step

anonymous · Answer

attachment

anonymous · Answer

i got 0, pi/2, pi, 3pi/2 as an answer but i dont think thats right...

anonymous · Answer

you get $\sin(2x)=0$ right?

anonymous · Answer

oh wait, maybe they are ...

anonymous · Answer

they look good to me

anonymous · Answer

ok because i was messing around and got 0, pi/3, 2pi/3, pi, 4pi/3 too @satellite73

anonymous · Answer

no that isn't right, your first answer was right

anonymous · Answer

ok thanks

anonymous · Answer

how did you like my rebus?

primeralph · Answer

@satellite73  Was that picture posted in honor of me?

anonymous · Answer

of course; it is "primer alf"

primeralph · Answer

Well, now I know how your childhood went. I'm truly sorry; really I am.

anonymous · Answer

it had a very productive childhood, it is my adulthood that is being misspent

primeralph · Answer

@satellite73  You know I was joking right?

primeralph · Answer

What I meant is  that you read really old books as a child. That book is the older version of a children's learning book.

anonymous · Answer

yes (i hope)