Question

Solve x^4 = 36x^2. Identify any double roots.

A. {0 (double root), 6, –6}

B. {–3, 3, 2 (double root)}

C. {0, 3, 2}

D. {6, –6}

Answer 1

Can anybody please explain how to solve this?

Answer 2

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Answer 3

A is the correct answer.

Answer 4

@Charollete can you please explain? if you don't mind

Answer 5

Sure:

bring over x^4 so you'd have \[36x ^{2}-x ^{4}\]

Factor an \[x ^{2} \] out so you'd have:\[x ^{2}(36-x ^{2})\]
Set \[x ^{2} = 0\] and \[(36-x ^{2}) = 0\]

You find that x = 0 in the \[x ^{2}\] portion. Factor the second portion: \[(36-x ^{2})\]
You find that it's a difference of squares: (x-6) and (x+6)

set both of those equal to 0:

(x-6) = 0 and (x+6) = 0

x = 6 and x = -6 and x = 0

Answer 6

Thank YOU SO MUCH!!!

Answer 7

No problem =)