Question

Solve (x + 2)^2 + 7(x + 2) = 18. Identify any double roots.

A. {–11, 0}

B. {–2, –7}

C. {–9, 2 (double root)}

D. {–2, 9 (double root)}

Answer 1

Do I simplify first or?...

Answer 2

Yeah simplify by finding that \[(x+2)^{2} = x ^{2}+4x+4\] Multiply out the 7(x+2) part to get 7x+14 add like terms so you get \[x ^{2}+4x+4+7x+4 = 18\] You get\[x ^{2}+11x+18=18\]
Subtract 18 from both sides:\[x ^{2}+11x = 0\]Factor an x out you find you get \[x(x+11) = 0\] set both x = 0 and (x+11) = 0 to find
x = 0 and x = -11

Answer is: A.

Answer 3

Thank you so much!!!

Answer 4

No problem.