Find all of the zeros of f(x) if f(x) = (x^2 – 4)^3. Identify any multiple zeros.

A. {4 (triple zero), –4 (triple zero)}

B. {4 (triple zero)}

C. {2, –2}

D. {2 (triple zero), –2 (triple zero)}

Question

Find all of the zeros of f(x) if f(x) = (x^2 – 4)^3. Identify any multiple zeros.

A. {4 (triple zero), –4 (triple zero)}

B. {4 (triple zero)}

C. {2, –2}

D. {2 (triple zero), –2 (triple zero)}

anonymous · Answer

Can anybody explain how to solve this?! how to start?

anonymous · Answer

This ones easier than you think: 
First just set it equal to 0$$(x ^{2}-4)^{3} = 0$$ Cube Root both sides:
$$(x ^{2}-4) = 0$$ Again another easy difference of squares we find that (x-2)(x+2) = 0

Solve for both of those we find:

x = 2 and x = -2 so answer is C

anonymous · Answer

Thank you so much!!! @Charollete

anonymous · Answer

Np @RH