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OpenStudy (anonymous):
OpenStudy (bahrom7893):
\[x^{-1}\] means \[\frac{1}{x}\]
OpenStudy (anonymous):
I factored and simplified and got \[\frac{ 2x(x+2)(x-3) }{ x^2 (x-4) (x+2) }\]
OpenStudy (anonymous):
is this correct?
OpenStudy (bahrom7893):
Let me check...
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OpenStudy (bahrom7893):
Top looks right...
OpenStudy (bahrom7893):
And so does the bottom. Now just cancel out some terms.
OpenStudy (anonymous):
(x+2) right?
OpenStudy (anonymous):
is there anything else I can simplify?
OpenStudy (bahrom7893):
Yes, what else?
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OpenStudy (anonymous):
I don't know :( sorry
OpenStudy (anonymous):
\[\frac{ 2x(x+2)(x-3) }{ x^2 (x-4) (x+2) }\]
From here, there are things you can cancel or simplify. Look for terms that are the same on the top and the bottom.
OpenStudy (bahrom7893):
They also have an x term in common :)
OpenStudy (anonymous):
So i just cancel it out or...?how ?
OpenStudy (anonymous):
When the same number is on the to as on the bottom, That = 1 so just cross them out.|dw:1375033113646:dw|
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OpenStudy (anonymous):
yes I understand about x+2, what I do not understand is the how the 2x and x^3 simplify :(
OpenStudy (bahrom7893):
\[x^2 = x*x\]
OpenStudy (anonymous):
Also, when dividing like terms with exponents - you subtract the exponents.
\[\frac{x^5}{x^3} = x^{5-3} = x^2\]