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Mathematics 13 Online
OpenStudy (anonymous):

Can anybody please explain how to simplify this?

OpenStudy (anonymous):

OpenStudy (bahrom7893):

\[x^{-1}\] means \[\frac{1}{x}\]

OpenStudy (anonymous):

I factored and simplified and got \[\frac{ 2x(x+2)(x-3) }{ x^2 (x-4) (x+2) }\]

OpenStudy (anonymous):

is this correct?

OpenStudy (bahrom7893):

Let me check...

OpenStudy (bahrom7893):

Top looks right...

OpenStudy (bahrom7893):

And so does the bottom. Now just cancel out some terms.

OpenStudy (anonymous):

(x+2) right?

OpenStudy (anonymous):

is there anything else I can simplify?

OpenStudy (bahrom7893):

Yes, what else?

OpenStudy (anonymous):

I don't know :( sorry

OpenStudy (anonymous):

\[\frac{ 2x(x+2)(x-3) }{ x^2 (x-4) (x+2) }\] From here, there are things you can cancel or simplify. Look for terms that are the same on the top and the bottom.

OpenStudy (bahrom7893):

They also have an x term in common :)

OpenStudy (anonymous):

So i just cancel it out or...?how ?

OpenStudy (anonymous):

When the same number is on the to as on the bottom, That = 1 so just cross them out.|dw:1375033113646:dw|

OpenStudy (anonymous):

yes I understand about x+2, what I do not understand is the how the 2x and x^3 simplify :(

OpenStudy (bahrom7893):

\[x^2 = x*x\]

OpenStudy (anonymous):

Also, when dividing like terms with exponents - you subtract the exponents. \[\frac{x^5}{x^3} = x^{5-3} = x^2\]

OpenStudy (anonymous):

Thanks a lot!!!

OpenStudy (anonymous):

Your Welcome.

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