Simplify the expression 4 over quantity of 3 x to the negative second power.
Is this the porblem? \( \dfrac{4}{(3x)^{-2} } \)
yes!
Look at the following rule of exponents: \(a ^{-n} = \dfrac{1}{a^n} \)
What the rule tells you is that if you have a negative exponent, it's the same as having a positive exponent in the denominator. Now let's use that rule of exponents for a negative exponent in the denominator to see what happens to the negative exponent.
\( \dfrac{1}{a^{-n}} \) \(= \dfrac{~~~1~~~}{\dfrac{1}{a^n}} \) \(= 1 \div \dfrac{1}{a^n} \) \(= 1 \times a^n \) \( = a^n\)
From here you see that a negative exponent in the denominator is a positive exponent in the numerator.
Now let's look at your problem. \(\dfrac{4}{(3x)^{-2} }\) \(= 4 \times (3x)^{2} \) Now can you finish it?
\[36x^{2}?\]
\(= 4 \times (3x)^{2}\) \(= 4 \times 9x^2\) \( = 36x^2\) You are correct. Good job!
thank you!!
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