Answer the questions below about the quadratic function. f(x)=-2x^2-8x-6 does the function have a minimum or maximum value? what is the functions minimum and maximum value? where does the minimum or maximum value occur?
A. Yes B. Find derivative and solve for df/dx = 0 C. Use your answer for df/dx=0 and plug into f(x) and solve
i don't understand
A: can have either or which one is it?
@mathmate
gabstersvee , you are doing calculus?
algebra 2 @theEric
So, the derivative stuff. Is that unfamiliar to you?
yes
Completely unfamiliar? Teacher never mentioned it?
no im taking an online course. its a series of random questions i am currently taking a quiz with this question
I gotcha. So I think the first step is to change the way it looks, with algebra. It'll be like the opposite of FOILing.
\[f(x)=-2x^2-8x-6\]
That's like the \(x^2+2x+1\) form of \((x+1)^2\). You want it in that second form!
i see
So, you have \(-2x^2-8x-6\). Do you know how to get it to its other form?
nope
http://www.algebrahelp.com/lessons/factoring/trinomial/ Well, I think we have to start guessing. There is "completing the square," but that only applies when the whole thing is equal to \(0\).
So, you have \(−2x^2 −8x−6\). Why not do something to make those all plus signs to make it easier? Hint: multiply by \(-1\).
That will get us started.
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