Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Manny has to run 6 errands between 10 and 5 on Saturday. He must get a haircut, wash his car, buy stamps, rent a video, return a book to the library, and buy some groceries. Assume that each errand will take 30 minutes and that Manny will do only one errand per hour. Manny will stop for a lunch break between 12 and 1. Use the information in the drawing to figure out a way for Manny to accomplish all 6 tasks.

OpenStudy (anonymous):

A. Describe two alternative orders in which Manny could complete his errands. B. What if Manny had 7 errands instead of 6? What would he need to do to adjust for the extra errand?

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

where are you stuck on this?

OpenStudy (anonymous):

I'm not sure how to start this.

jimthompson5910 (jim_thompson5910):

Describe two alternative orders in which Manny could complete his errands. if you think of the errands as A, B, C, D, E, F, G then you can rearrange those errands in any order you like (eg: ABCDEFG or GFABCED) list two different orders that haven't been written yet

jimthompson5910 (jim_thompson5910):

oh sorry, it's A through F, not A through G

OpenStudy (anonymous):

But the attachment shows what time each place is open so I have to order it to match when the places are open.

jimthompson5910 (jim_thompson5910):

ok so not all orders will work

jimthompson5910 (jim_thompson5910):

so prioritize the ones that close early (ie put them first) over the ones that don't close as early

jimthompson5910 (jim_thompson5910):

make sense?

OpenStudy (anonymous):

Also can lunch and an errand happen in the same hour?

jimthompson5910 (jim_thompson5910):

probably not, so you might have to squeeze in two errands in one hour

jimthompson5910 (jim_thompson5910):

then again, he could cut his lunch short easily

jimthompson5910 (jim_thompson5910):

so anything is possible

OpenStudy (anonymous):

Well in the problem it says "Assume that each errand will take 30 minutes and that Manny will do only one errand per hour."

jimthompson5910 (jim_thompson5910):

ok then you have to put it in the lunch hour

OpenStudy (anonymous):

Okay. So I could do. A:Video B: Post Office C: Barbershop D: Library E: Grocery F: Car Wash So one could be B, D, A, C, F, E

OpenStudy (anonymous):

Another could be B, C, D, F, E, A

OpenStudy (anonymous):

Is that right?

jimthompson5910 (jim_thompson5910):

sorry one sec, got distracted

jimthompson5910 (jim_thompson5910):

hmm I would swap E with C in both cases because E closes much earlier than C

OpenStudy (anonymous):

E closes at 12am. E closes the latest out of every place.

jimthompson5910 (jim_thompson5910):

oh 12 am, not 12 pm, nvm lol

jimthompson5910 (jim_thompson5910):

my bad

jimthompson5910 (jim_thompson5910):

then you could put that last if you wanted

OpenStudy (anonymous):

Hahaa. I was confused for a sec there.

jimthompson5910 (jim_thompson5910):

its ok, misread and thought things wrong for a sec, but everything looks good

OpenStudy (anonymous):

Okay well now that part A is done how would you do part B?

jimthompson5910 (jim_thompson5910):

if he had 7 errands instead of 6, he would have to either do 2 errands in one hour or cut his lunch short so he could do that 7th errand during the lunch hour

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!