Question

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is 4x + y - 2 = 0?

4x-y= 13?am i correct

Answer 1

Show me your steps, Student.

Answer 2

y=mx+b
y=4x+0
y=4x

Answer 3

Solve your equation for y to find the slope.

Answer 4

idk how

Answer 5

Everything is on the left side, you want everything except the y on the right side. So, use inverse operations to move the terms.

Answer 6

\(4x + y - 2 = 0\)
\(-4x ..... ..= -4x\)

Answer 7

4x-2=y

Answer 8

4 x 4=16-2=14

Answer 9

What?

Answer 10

Subtract \(4x\) from each side.

Answer 11

Then add 2 to each side.

Answer 12

the equation was 4x + y - 2 = 0 i moved 4x and -2 to the left

Answer 13

right i mean

Answer 14

\(4x + y - 2 = 0\) Can be re-written as:
\(y=-4x+2\) or
\(4x-2 = -y\) which needs to be multiplied through by a -1 to get \(-4x+2=y\)

Answer 15

Do you follow?

Answer 16

4x-y=0?

Answer 17

I think you're jumping ahead without understanding the process. I know you have a lot to do and limited time to do it, but please stay with me on this one. Ok?

Answer 18

ok

Answer 19

The equation of the given line is \(y=−4x+2\) Do you understand how I got that?

Answer 20

you multiplyed 4x-2=-y

Answer 21

Good. Next, realize that a perpendicular line has a slope that is the negative inverse of the given line. So, what is the negative inverse of -4?

Answer 22

4

Answer 23

The inverse means to flip the fraction.
\[4 = \frac{4}{1}\]

Answer 24

-1/4

Answer 25

The inverse of -4 is \(\frac{1}{4}\)

Answer 26

So, that is the slope of your new line.
Use the point-slope formula to get the equation of the new line.
\[y – y1 = m(x – x1)\]

Answer 27

m= 1/4 Find \(x_1\) and \(y_1\) from the point given in the equation.

Answer 28

\[y – y_1 = m(x – x_1)\]

Answer 29

y=-1/4x+b?

Answer 30

The slope is positive 1/4.

Answer 31

Use the point-slope formula to get the equation:
\(y – y_1 = m(x – x_1)\)

Answer 32

y=1/4(4)+-3

Answer 33

=13

Answer 34

x and y will remain in the equation. You will substitute the numbers in your point for the \(x_1\) and \(y_1\).

Answer 35

im not sure how to do that

Answer 36

Using point (4,-3) and point-slope formula \(y – y_1 = m(x – x_1)\) You will get\( y+3 = \frac{1}{4}(x-4)\). Does that make sense?

Answer 37

\(m= \frac{1}{4}\)
\(y_1 = -3\)
\(x_1 = 4\)

Answer 38

i thnik i remember this can you show the equation includin x1 and y1 in a drawing?

Answer 39

Not on this site. I don't know how. Let me see if I can find a better website....

Answer 40

Try this:
http://www.mathsisfun.com/data/function-grapher.php

Answer 41

If the graph doesn't show up, just put the two equations in.
y=-4x+2
y=1/4x+2

Answer 42

im sorry im having a hard thime with this can we move on?

Answer 43

Sure - as long as you promise me that you will continue to study after you complete the test so you will be ready for the next class.

Answer 44

i will thank you