With exponential functions, the formula is f(x) = b^(x-h) + k The h moves it left or right. The k moves it up or down. If h is negative, which way will it go: left or right? If k is negative, which way will it go: up or down?
Okay, so if the function were f(x) = 11^x And the function is moved right 5 and down 8 the new function g(x) = 11^(x+5) - 8 ????
@FutureMathProfessor
What do you mean?
Talking to yourself?
:)
No. He said something. he must've deleted the comment DX
He said that 11^x was completely out of the realm. And I don't see how
Ugh, can someone please just explain DX
When a function is expressed in the form f(x)=a^(x-h)+k h and k represent translations to the right and to the top respectively. Evidently, if any of the two is negative, the direction is reversed.
wait. so when it is (x-h) it goes right, and when it is (x+h) it goes left?
- right + left
Think of is as moving the graphing paper away while keeping the curve still.
is it that way with the k too?
Yes, if h and k are both positive.
The equivalent statement of what you just interpreted would be: translation to the right if h is positive, and to the left if h is negative.
Primer just said the opposite of what you just said DX
@SavannahWillett , Me and @mathmate are saying the same thing.
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