check my answer? y=x^2-2x is minimum because the x term is positive so it would be open upward and the vertex is (1,-1)

y=-2x^2+4x-3 is maximum because the x term is negative so it would be open downward and the vertex is (1,-3)

Question

check my answer? y=x^2-2x is minimum because the x term is positive so it would be open upward and the vertex is (1,-1)

y=-2x^2+4x-3 is maximum because the x term is negative so it would be open downward and the vertex is (1,-3)

anonymous · Answer

@jim_thompson5910 did i get this right?

campbell_st · Answer

they 1st one is almost correct. , but I would say the leading coefficient is positive or 

the general for of the curve is 

$$y = ax^2 + bx + c $$  a determines concavity... 

so the parabola is concave up because the coefficient of the leading term is positive, with a vertex at (1, -1) and a minimum at y = -1

the minimum means what is the lowest value in the range that the curve gets to. 

for the 2nd question I think your vertex is incorrect based on the equation posted

I think its (1, -1) 

but the curve is concave down because   the coefficient of the leading term is negative, the vertex is (1, -1) and has a maximum value at y = -1

hope that makes sense.

anonymous · Answer

so both of their vertexs is (1,-1)? @campbell_st