Question

picture posted

Answer 1

is this A, D AND E?

Answer 2

@campbell_st

Answer 3

@Mertsj

Answer 4

@primeralph

Answer 5

no idea im still in algebra 1

Answer 6

Okay, so continuous random variable is one which takes an infinite number of possible values.

Suppose a random variable X may take all values over an interval of real numbers. Then the probability that X is in the set of outcomes A, P(A), is defined to be the area above A and under a curve. The curve, which represents a function p(x), must satisfy the following:

1: The curve has no negative values (p(x) > 0 for all x)
2: The total area under the curve is equal to 1.
A curve meeting these requirements is known as a density curve.
(Taken from http://www.stat.yale.edu/Courses/1997-98/101/ranvar.htm)

Now all we gotta do is find the graph that matches the conditions.

Answer 7

yea I know that the curve ha to equal 1

Answer 8

And the curve cannot go below the x axis.
So if there are 10 of those squares under the curve, you're good. So A matches

Answer 9

B doesn't match (only 9 squares, 9*0.1=0.9, which is not 1)

Answer 10

C doesn't match - the graph goes below x-axis.

Answer 11

D matches

Answer 12

yeah I said A & D

Answer 13

but I dint know about E.. how do u know if E equals 1?

Answer 14

well there are a few ways... first of all form a square in your head, and then find the area, and then divide it by 2.

Answer 15

it matches. 20*.1/2 = 10*.1=1

Answer 16

where did u get 20 from

Answer 17

when i formed that square in my head, i counted 20 boxes.

Answer 18

im confused

Answer 19

oh like the square surrounding the triangle?

Answer 20

like I kinda get what ur saying actually... so wait ur sure its E also?

Answer 21

yes

Answer 22

ok.

Answer 23

help w/ this problem?

Answer 24

@amistre64 @satellite73 @Mertsj help!

Answer 25

is it 81/ something

Answer 26

@kropot72

Answer 27

expected value is just the mean of the set ...

Answer 28

he got 0 bases 450 times: 0 added together 450 times is 0(450) = 0
he got 1 bases 190 times: 1 added together 190 times is 1(190) = 190
he got 2 bases 32 times: 2 added together 32 times is 2( 32) = 64
he got 3 bases 10 times: 3 added together 10 times is 3( 10) = 30
he got 4 bases 10 times: 4 added together 10 times is 4( 10) = 40
___________ ------
# trys: 692 total bases: 324

bases/number of trys = average bases