Question

Please, just one person at a time.
log(2)256 The base is two.
How do you solve this?
This is what I did:
log(2)256 = x
2^x = 256
x = 8
Did I do this right?

Answer 1

yes

Answer 2

yes

Answer 3

rewrite 256 as a power of 2

well 256 = 2^8

so you are looking as solving

\[\log_{2}(2^8) = x\]

so applying some log laws

\[\log(x^a) = a \times \log(x)\]

and when the base of the log and exponent are the same

\[\log_{a}(a) = 1\]

so now apply these laws to your question in the rewritten form to find the value of x

Answer 4

Thank you