Question

what are foci of the the graph 4x^2 - 9y^2 = 36

Answer 1

\(\bf 4x^2 - 9y^2 = 36 \implies \cfrac{4x^2}{36}-\cfrac{ 9y^2}{36} = 1\)

Answer 2

\(\bf \cfrac{\cancel{4}x^2}{\cancel{36}}-\cfrac{ \cancel{9}y^2}{\cancel{36}} = 1
\implies \cfrac{x^2}{9}-\cfrac{ y^2}{4} = 1\)

Answer 3

that means that your a^2 = 9, b^2 = 4
notice the center, is at the origin

also keep in mind that the distance from the center is "c" and \(\bf c^2 = a^2+b^2\)

Answer 4

also notice that the fraction with the POSITIVE sign, is the one with the "x" variable
that means is a horizontal traverse axis, so it's opening to the left and right

so find "c" distance, and move left and right THAT MUCH from (0, 0)

Answer 5

so the answer would be ?

Answer 6

so, what did you get for "c"?

Answer 7

(0,3.6)

Answer 8

hmm I got something else :/

Answer 9

wat you get?

Answer 10

actaully nope, you're correct

Answer 11

I was getting dual squared heheh

Answer 12

was squaring the 9, but 9 is already squared :(

Answer 13

http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIrc3FydCgoNHheMi0zNikvOSkiLCJjb2xvciI6IiMwMDAwMDAifSx7InR5cGUiOjAsImVxIjoiLXNxcnQoKDR4XjItMzYpLzkpIiwiY29sb3IiOiIjMDAwMDAwIn0seyJ0eXBlIjoxMDAwfV0-