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Mathematics 6 Online
OpenStudy (anonymous):

Ratio test

OpenStudy (anonymous):

I have this series\[\sum_{n=1}^{∞}(1-\cosh(1/n))\] and I need to show the ratio test doesn't work i.e. \[\lim_{n \rightarrow ∞}\frac{ a _{n+1} }{ a _{n} }=1\] But I can't solve it, can someone help me?

OpenStudy (uri):

Test? You're in a test? :p aw

OpenStudy (anonymous):

No I using the Ratio Test to Determine if a Series Converges. :)

OpenStudy (anonymous):

Orrh i thinke i got it.. L Hospital rule?

OpenStudy (anonymous):

\[a_n=1-\cos h (1/n)=1-\frac{e^{1/n}+e^{-1/n}}{2}=\frac{2-e^{-1/n}-e^{1/n}}{2e^{1/n}}\] \[a_{n+1}/a_n=?\]

OpenStudy (anonymous):

\[a_{n+1}/a_n=\frac{ 2-ee^{1/n}-ee^{-/n} }{ 2ee^{1/n} }\frac{ 2e^{1/n} }{ 2-e^{1/n}-e^{-1/n} }=\frac{ 2-ee^{1/n}-ee^{-/n} }{ 2e-ee^{1/n}-ee^{-1/n}}\]

OpenStudy (anonymous):

Thank you @Jonask

OpenStudy (anonymous):

there s an error

OpenStudy (anonymous):

i put e^1/n without having not to do so

OpenStudy (anonymous):

downstairs i mean

OpenStudy (anonymous):

but anyway it does not affect the final ratio we got over there

OpenStudy (anonymous):

:)

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