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OpenStudy (anonymous):
Use the properties of logarithms to expand the following logarithms completely.
log(5) ^3»(xz)
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OpenStudy (anonymous):
The little arrows are a radical.
OpenStudy (psymon):
The 5 is just raised to the 3rd and not a base, correct?
OpenStudy (anonymous):
The five is the base.
OpenStudy (anonymous):
The three is a cube root of xz
OpenStudy (jdoe0001):
\(\large log_5\sqrt{3xz} \ \ \ ?\)
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OpenStudy (psymon):
Gotcha. And I'm still not used to how people write out equations like jdoe just did, so that will always look funky xD
OpenStudy (jdoe0001):
\(\bf \huge log_5(\sqrt[3]{xz}) \) then
OpenStudy (anonymous):
Yes.
OpenStudy (jdoe0001):
don't forget the \( hehe
OpenStudy (anonymous):
Okay XD
But anyways. Now that we have the problem written out so it makes sense, help me solve it?? XD
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OpenStudy (jdoe0001):
keep in mind that \(\bf \huge a^{\frac{n}{m}} = \sqrt[m]{a^n}\)
OpenStudy (jdoe0001):
from there just apply the log rule for the exponents
OpenStudy (anonymous):
so it's x (z/3)????
OpenStudy (anonymous):
\[\log_{5}\sqrt[3]{xz} = \log_{5}(xz)^{1/3} = \frac{1}{3}\log_5(xz)=\frac{1}{3}(\log_5x+\log_5z)\]
OpenStudy (jdoe0001):
as shown by @walac ^
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OpenStudy (jdoe0001):
the exponent comes out as coefficient, then you expand the factors inside as shown
OpenStudy (anonymous):
Ohhh, okay
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