Use the properties of logarithms to expand the following logarithms completely. log(5) ^3»(xz)
The little arrows are a radical.
The 5 is just raised to the 3rd and not a base, correct?
The five is the base.
The three is a cube root of xz
\(\large log_5\sqrt{3xz} \ \ \ ?\)
Gotcha. And I'm still not used to how people write out equations like jdoe just did, so that will always look funky xD
\(\bf \huge log_5(\sqrt[3]{xz}) \) then
Yes.
don't forget the \( hehe
Okay XD But anyways. Now that we have the problem written out so it makes sense, help me solve it?? XD
keep in mind that \(\bf \huge a^{\frac{n}{m}} = \sqrt[m]{a^n}\)
from there just apply the log rule for the exponents
so it's x (z/3)????
\[\log_{5}\sqrt[3]{xz} = \log_{5}(xz)^{1/3} = \frac{1}{3}\log_5(xz)=\frac{1}{3}(\log_5x+\log_5z)\]
as shown by @walac ^
the exponent comes out as coefficient, then you expand the factors inside as shown
Ohhh, okay
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