Okay, this is when I really feel perplexed. May someone please help explain this? –24m^2n^6 – 8mn^5 – 32n^4
This is how far I've gotten, -8n(3m^2n^5 + mn^4 + 4n^3)
You can factor out more than 1 n
-8n^2(3m^2n^4 + mn^3 + 4n^2)
And now with this I knew to make them positive because the negative coefficient will make them negative again in the end result.
What is the largest number of n's you can factor out?
it should be n^3... correct?
I was hesitant to say four because of that last number. If I factor out 4, then the end result may make that -32n^4 to -32n^5, right?
$$–24m^2n^6 – 8mn^5 – 32n^4$$ $$=-8n^4(3m^2n^2+mn+4)$$
If you factor out a \(n^4\) out of the last term, the n disappears from that term. but the coefficient does not.
I gotcha. And thank you @skullpatrol, it helped to look at it while @gypsy1274 is explaining.
Ok, taking this, −8n^4 (3m^2n^2 + mn + 4) To break it down further Am I correct with -8n^4(3mn + 3) (mn + 1)?
If you FOIL (3mn+3)(mn+1) will you get \(3m^2n^2+mn+4\)? I don't think so....
The only factors of 3 are 3 and 1 so start with that. (3mn )(mn ) Now find the factors of 4 that will work. It will take a bit of trial and error.
So aside from 4 and 1 I have 2
Use the 4 and 1 see of you can find the correct placement and sign to factor.
I understand -4 and -1 gives a positive 4 when multiplied but in regard to addition I realize tht I'm still wrong
when I tried to multiply -2 and -2 I still got positive 4 but then to get -mn I am simply stuck
I think you just pointed out my mistake....verifying...
Oohhh, Noooo! Time to call in reinforcements.... @skullpatrol What am I doing wrong? @uri How does \(-8n^4(3m^2n^2+mn+4)\) factor?
I started with \(-8n^4(3mn+4)(mn-1)\) but that doesn't work.
–24m^2n^6 – 8mn^5 – 32n^4 -8n^4(3m^2n^2+ mn+4) You are correct till here.
Yes, but does the remaining trinomial factor?
It ends here.
@gypsy1274, @skullpatrol, @uri Thanks for your help
Thanks for trying to learn.
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