posted pic
@primeralph
@mebs
The meaning of E(x) is the expected value in a distribution. \[E(x) = \frac{ x }{ \mu} \] where mew is usually the mean.
what is mew?
Its the symbol \[\mu \]
so ho would I plug it in to solve
its called the population mean right?
In your case its means Probability.. I think \[0.07 = \frac{ 13 }{ \mu } \]
ok so then I would solve for the u right?
Do a few of them and see what mew is...its been a while...
well in my notes its a population mean.. what do u mean do a few of them
well there are a few to do like for 0.21 and 0.17...
The expected value is what you expect to get .... its not really the actual probability..
yea I know, I just don't understand ho id solve though. for the one u plugged in above, id multiply 7 times the mew and then do 13 divided by that right?
you could try that.
its not on your calculator... its a generic term...you could use c or d of f or lamda..
yea but if I multiply that mew by 7 what would I get..
@gypsy1274
you would get 7mew... why would you do that?
ok. so how do I even solve for the expected value then?
just graph it... |dw:1375049464527:dw|
and then???
it looks something like and M and they something after that
Alright ... Expected value is what you usually expect to come up the most right.... So you see that 21 comes up 25% of the time..
21??
for x or y?
im sorry I just don't understand this very much... I really don't like this unit :(
Just do this E(x) = (13 * 0.07)+ (16 * 0.21) + (17*0.17)...etc really the expected value is the variable with the most frequent occurrences.
I never like this unit either haha that's why I don't remember that well :P...
Just continue what I started at the E(x) part and tell the sum of those products.
ok so is this what u have to do IN ORDER TO FIND the EXPECTED VALUE??? multiply X BY p(X) AND KEEP DOING THAT AND ADD EM ALL UP????
yes
wow. :p u should've just said tht.
ok so when I multiply (13*0.07) + (16*0.21) + ..... i got 20.42?
sorry haha do you understand what expected value is though.. its not necessarily the most frequent outcome alright..
yea I get it. so that's how I will always frind the expected value right?
than that's your answer let me check yea...
ok check it
no its different for a standard distribution and hyper geometric distribution and etc... but yea your right..
ok.. (and Idk what standard and geo is.. and the difference between them)
ok so my answer is right? k ill submit it then
alright fingers crossed..
ill tell u when its right.. but I have a quick question before that
what would that be?
if they give u a table and ask u to find the standard deviation for X, "the number that comes up on the die" how do u find it
\[\mu=\sum_{i=1}^{n}x _{i}p \left( x _{i} \right)\] for discrete distributions.
Well the standard diviation is what pgpilot says expect the xi means x - u
\[\mu=E \left( X \right)\]
so wait what
for example here's this question
\[VAR \left( X \right)=E \left( X ^{2} \right)-\left( E \left( X \right) \right)^{2}\] for discrete distributions and \[\sqrt{VAR \left( X \right)} = SD \left( X \right)\]
|dw:1375050815278:dw|
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