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Probability
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A package contains 6 candy canes, 2 of which are cracked. If 4 are selected, find the probability of getting no cracked candy canes.
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are they selected and replaced back into the bag? or left out?
left out
okay. you will need to do this: there are 6 total, and 2 cracked. so while pulling the first out, the probability of selecting a normal cane would be: \[\frac{ 4 }{ 6 } \] since they are left out, you would only have 5 left, therefore the next probability would be \[\frac{ 3 }{ 5 }\]
next would be: \[\frac{ 2 }{ 4 }\] followed by: \[\frac{ 1 }{ 3 }\]
thanks
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do you follow up to this point?
yes
okay great. do you know what to do with the 4 fractions now?
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