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Mathematics 16 Online
OpenStudy (anonymous):

6z3–27z2+12z

OpenStudy (anonymous):

3z(2z^2 - 9z +4)?

HanAkoSolo (jamierox4ev3r):

the question is the factored form of what you just typed.

OpenStudy (anonymous):

Yes, that is correct.

HanAkoSolo (jamierox4ev3r):

6z^3-27x^2+12z=3z(2z^2-9z+4)

HanAkoSolo (jamierox4ev3r):

they equal each other, one is the factored form of the other

OpenStudy (anonymous):

gotcha. I su

OpenStudy (anonymous):

I'm just trying to take the baby steps to factor it further

OpenStudy (uri):

Yayy! @Sabot3 is understanding it. :3

OpenStudy (anonymous):

lol :-) thanks Uri, I almost got discouraged with one of the other member's response

OpenStudy (anonymous):

This one can be factored further. Checked it twice, I'm sure of it.

OpenStudy (anonymous):

Trying to get to that point So far, I'm here 3z(2z )(z )

OpenStudy (anonymous):

trying to come up with the two numbers for 9 and 4

OpenStudy (anonymous):

It is just trial and error at this point. You know the factors of 4 so just try each pair.

OpenStudy (anonymous):

yes ma'am

OpenStudy (anonymous):

I've got nothing but frustration now. I'm not sure how to get 9

OpenStudy (anonymous):

\(3z(2z-1)(z-4)\)

OpenStudy (anonymous):

#lost again... :-(

OpenStudy (anonymous):

Don't look at it that way.... When I can't find the factors easily, I use the quadratic formula. It's a few more steps than factoring, but much less frustration.

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