6z3–27z2+12z
3z(2z^2 - 9z +4)?
the question is the factored form of what you just typed.
Yes, that is correct.
6z^3-27x^2+12z=3z(2z^2-9z+4)
they equal each other, one is the factored form of the other
gotcha. I su
I'm just trying to take the baby steps to factor it further
Yayy! @Sabot3 is understanding it. :3
lol :-) thanks Uri, I almost got discouraged with one of the other member's response
This one can be factored further. Checked it twice, I'm sure of it.
Trying to get to that point So far, I'm here 3z(2z )(z )
trying to come up with the two numbers for 9 and 4
It is just trial and error at this point. You know the factors of 4 so just try each pair.
yes ma'am
I've got nothing but frustration now. I'm not sure how to get 9
\(3z(2z-1)(z-4)\)
#lost again... :-(
Don't look at it that way.... When I can't find the factors easily, I use the quadratic formula. It's a few more steps than factoring, but much less frustration.
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